中文摘要：

利用高温固相法制备了BaMoO4：Eu3＋发光材料,采用X射线衍射（XRD）和荧光光谱仪对样品进行测试。结果表明,在800℃时得到BaMoO4纯相,属四方晶系。激发光谱由一个宽带和处在350 nm后的若干个线状谱组成,宽带归属于Eu3＋—O2-电荷迁移吸收带（CT）,线状谱属于Eu3＋的f—f激发跃迁吸收。发射光谱由5D0—7F1（591 nm）,5D0—7F2（615 nm）,5D0—7F3（654 nm）和5D0—7F4（702 nm）四组峰组成,其红光5D0—7F2辐射跃迁发射最强,对应Eu3＋的电偶极跃迁。

英文摘要：

The BaMoO4∶Eu3＋ phosphors were synthesized by solid-state method and were characterized by X-ray diffraction（XRD） and photoluminescence spectra.XRD analysis confirmed the formation of BaMoO4 at 800 ℃ and exhibited a tetragonal crystal structure.The excitation spectrum of samples showed one broad band and some peaks located behind 350 nm.The former was attributed to the charge transfer transition of Eu3＋—O2-,while the latter belonged to the f—f transitions of Eu3＋ ions.The emission spectrum shows four peaks at 591,615,654 and 702 nm,respectively.The dominant peak is located at 615 nm due to the 5D0—7F2 electric dipole transition of Eu3＋.