制备了晶体包合物反式-9,10-二氢-9,10-二对甲苯基-9,10-菲二醇·苯,通过IR和粉末X-射线衍射对包合物进行了表征,运用1H NMR计算主客体摩尔比为1∶ 1,单晶X-射线衍射分析表明,互为对映体的两对主体分子构成了一个空腔,客体分子苯以适当方式填充在主体分子构筑的空腔中,从而形成了隧道型晶体包合物.
Crystal inclusion compound, trans-9,10-di (p-tolyl) -9,10-dihydro-9,10-phenanthrenediol · benzene, was prepared and characterized by IR and powder XRD. The molar ratio of host to guest is 1:1 calculated by ^1H NMR. Four cycle X-ray diffraction showed that guest molecules benzene were filled in a proper manner in the tunnel formed by two pair of host isomers, thus forming tunnel-shape crystal inclusion compound.