设d是大于1的正整数.本文运用初等数论方法证明了:如果d的素因数p都适合p=2或者P≡±3(rood8),则方程2x(x+d)(x+2d)(x+3d)=y(y+d)(y+2d)(y+3d))仅有正整数解(x,y)=(4d,5d).
Let d be a positive integer with d 〉 1. In this paper, using some elementary number theory methods, we prove that if every prime divisor p of d satisfies either p = 2 or p ≡± 3(mod 8), then the equation 2x (x + d) (x + 2d)(x + 3d)= y(y+ d)(y + 2d)(y + 3d) has only the positive integer solution (x, y) = (4d, 5d).