设p是奇素数,给出了方程P^a+p^b-P^c=z^2,a≥b≥c的所有可使口为偶数的非负整数解(a,b,c,z).
In this paper, all nonnegative integer solutions (a, b, c,z) of the equation P^a+p^b-P^c=z^2, a ≥b≥c≥0,2|a are given under the condition that p be an odd prime.