中文摘要：

采用涂刷法制备铱、钌摩尔比（Ir：Ru）分别为1：2、1：1和2：1的3种RuO2-IrO2/Ti修饰电极.5 g/L苯酚溶液中循环伏安（CV）曲线测试结果表明,Ir：Ru为1：2的RuO2-IrO2/Ti修饰电极没有出现明显的氧化峰,而Ir：Ru分别为1：1、2：1的RuO2-IrO2/Ti修饰电极分别在0.83、0.90V处出现明显的氧化峰.0.5 mol/L硫酸溶液中的极化曲线测试结果表明,Ir：Ru分别为1：2、1：1、2：1的3种RuO2-IrO2/Ti修饰电极的析氧电位分别为1.20、1.25、1.35 V.一定条件下的苯酚降解试验结果表明,160 min后Ir：Ru分别为1：2、1：1、2：1的3种RuO2-IrO2/Ti修饰电极的苯酚去除率分别达到74.3％、82.3％和94.6％.可见,Ir：Ru为2：1的RuO2-IrO2/Ti修饰电极的析氧电位最高,苯酚去除率最高,电催化效果最好.

英文摘要：

Three different RuO2-IrO2/Ti electrodes with Ir： Ru was 1： 2,1： 1 and 2： 1 were prepared using brushing method.Cyclic voltammetry of 3 anodes was measured in 5 g/L phenol solution.Results showed that the RuO2-IrO2/Ti anode of Ir： Ru=1： 2 had no oxidation peak,while there was an obvious oxidation peaks occurred at 0.83,0.90 V respectively for Ir： Ru=1： 1 anode and Ir： Ru=2： 1 anode.Polarization curves were measured in 0.5 mol/L sulfuric acid solution,and the oxygen evolution potentials of Ir： Ru=1： 2,1： 1 and 2： 1 anodes were 1.20,1.25,1.35 V respectively.Phenol degradation test was conducted under certain conditions,the phenol removal efficiency of 3 anodes were 74.3%,82.3% and 94.6% after 160 min of electrical catalytic degradation.As a conclusion,the RuO2-IrO2/Ti anode of Ir： Ru was 2： 1 had the highest oxygen evolution potential and the best performance of electro-catalysis on phenol degradation.