用富氢材料防护产额为108个/s的D-T中子发生器,当富氢材料厚度大于76cm时,其中子辐射剂量低于0.025mSv/h.为降低防护体厚度,用铜和含硼聚乙烯组成的双层材料作为14 MeV中子防护体.Monte Carlo(MCNP)计算结果表明,若中子辐射剂量小于0.025mSv/h,则双层材料的最小厚度为52cm,硼的质量分数为1.00%,铜和含硼聚乙烯的厚度分别为37cm和15cm.
If hydrogen-rich material is used to shield the 14 MeV neutrons produced by D-T neutron generator whose neutron yield is 108 n/s,its thickness must be more than 76 cm to make the neutron radiation dose less than 0.025 mSv/h.In order to decrease the thickness,the bilayer material consisted of copper and boron-polyethylene was used as 14 MeV neutron shielding material.The result of the calculation shows that the minimum thickness of the bilayer material is 52 cm,in which the thicknesses of copper and boron-polyethylene are 37 cm and 15 cm and the content of boron is 1.00%.