中文摘要：

以2，3-二氨基甲苯为原料经过氨基保护、澳代、水解等反应制备2，3-二氨基苯甲醇，后者与芳香醛缩合成苯并咪唑，再经Mn02氧化、缩合生成2-（4-（4-（羟甲基）-1H-苯并[d]咪唑-2-基）-1H-苯并[d]咪唑-2-基）苯酚。经1^H—NMR对中间体和目标产物进行结构表征，并研究了产物的紫外、荧光性质，结果表明目标化合物能选择与Zn^2＋进行配位，产生较强的荧光，荧光量子收率为0．64，斯托克斯位移为142nm。

英文摘要：

2-（4-（4- （hydroxymethyl）-I H-benzo [- d] imidazob2-yl）-I H-benzo [d-] imidazol-2-yl） phenol was synthesized with （2,3-diaminophenyl） methanol prepared from 3-methylbenzene-1,2- diamine as the raw materials, through amino protection, bromide, hydrolysis reaction, oxidation and condensation. The molecular structures of the intermediates and the target compound were confirmed by 1^ H-NMR. UV and fluorescence properties of end product were researched, the results show that the compound can be coordinated with Zn^2＋, resultilag in strong fluorescence, fluorescence quantum yield of 0.64, Stoke＇s shift of 142nm.