研究了当n〉2k+m^*时.满足E(S,[f^n(μfm+λ)]^(k))=E(S,[g^n(μg^m+λ)]^(k))的整函数f与g的唯一性理论.其中S={1,ω,…ω^l-1},l≥4.
Study the uniqueness of entire functions f and g such that E (S,[f^n(μfm+λ)]^(k))=E(S,[g^n(μg^m+λ)]^(k) where N〉2k+m^* and S={1,ω,…ω^l-1},l≥4.