用对曲率a一致的方法证明了:若M^m(a)为配有度量 G=1/(1+a/4 p^2)^2m∑i=1 du^i×du^i,p^2=m∑i=1(u^i)^2的完备化单连通黎曼模型,M为M^n+1(a)中的闭定向超曲面,则有Minkowski积分公式∫M 4-ap^2/4+ap^2 Hk-1dA+∫M pHkdA=0,k=1,2…,n.其中总为M的第k个平均曲率,P为支持函数.
The following theorem is proved by a uniformly argument with respect to a. Let M^m(a) be the completed simply connected space form with metric G=1/(1+a/4 p^2)^2m∑i=1 du^i×du^i,p^2=m∑i=1(u^i)^2 If M is a closed oriented hyper surface in M^n+1(a), then there are Minkowski integral formulas as the following ∫M 4-ap^2/4+ap^2 Hk-1dA+∫M pHkdA=0,k=1,2…,n where Hk is the k-th mean curvature and p is the support function.