研究Zn上的四元数代数Zn[i,j,k]的零因子和单位群,给出Zn[i,j,k]的零因子个数和Zn[i,j,k]的单位群阶的计算公式,证明Zn[i,j,k]≌M2(Zn)的充分必要条件是n为奇数,并且完全决定了Zn[i,j,k]的单位群结构.
We investigate the zero-divisors and the unit group of quaternion algebra over Zn which is denoted by Zn[i,j,k] and obtain the calculating formulas of the number of zero-divisors and the order of the unit group of Zn[i,j,k].We prove that Zn[i,j,k]≌M2(Zn)if and only if n is odd.In addition,the structure of the unit group of Zn[i,j,k] are completely determined.