通过高温固相反应合成了La1/3NbO3∶Sm3+荧光粉.样品的荧光光谱表明,La1/3NbO3∶Sm3+荧光粉最强的激发带在406 nm,对应于Sm3+的6H5/2→4K11/2跃迁,属于近紫外区(365~410 nm).当激发波长为406nm时,样品的最强发射峰位于596 nm,是由Sm3+的4G5/2→6H7/2跃迁而产生的.因此,La1/3NbO3∶Sm3+可以作为基于近紫外激发的白光发光二极管(LED)的红光材料.而且,La位共掺杂Sr2+,Ba2+和Bi3+使样品的荧光强度大大增加,在最佳掺杂浓度时的量子产率分别为5.4%,7.5%和5.3%.
La1/3NbO3∶ Sm3+ phosphor was synthesized by solid state reaction at high temperature and its photoluminescence properties were investigated.Its strongest excitation band is at 406 nm,ascribed to 6H5/2→4K11/2 transition of Sm3+ in the range of near-ultraviolet region(NUV,365—410 nm).And its strongest emission peak is at 596 nm,attributed to 4G5/2→6H7/2 transition of Sm3+.As a result,La1/3NbO3∶ Sm3+ phosphor shows great potential for future application as alternative red-emitting NUV-based white LEDs.The luminescence intensity can be strongly enhanced by codoping cation in the La-site,namely Sr2+,Ba2+ and Bi3+.And the quantum yield is 5.4%,7.5% and 5.3% for Sr2+,Ba2+ and Bi3+ codoped samples respectively with the optimum doping concentration.