研究了二阶Neumann边值问题{u″+f(t,u,u')=s,t∈(0,1),u'(0)=u'(1)=0解的个数与参数s的关系,其中f∈C([0,1]×R2,R),s∈R。运用上下解方法及拓扑度理论,获得存在常数s1∈R,当ss1时,该问题至少有两个解。
We study the relationship between s and the number of solutions of the second-order Neumann boundary value problem{u″ + f( t,u,u') = s,t∈( 0,1),u'( 0) = u'( 1) = 0,where f∈C( [0,1]× R2,R),s∈R is a parameter. By using the method of the upper and lower solutions and topological degree techniques,we obtain that the problem has no solution,at least one solution and at least two solutions,when s s1,s = s1,s s1,respectively.