利用May谱序列确定了经典Adams谱序列中一类非平凡元素,当P≥7,4≤S〈P时,g0δ≠0 Ext1+2+(Z/p,Z/p),其中to(s)=q(sp3+(s-1)p2+(5—1)p+S-1)+s-4.
It's determined that the nontrivial of the 3-families element g03s ve 0 E Ext'A+2'to(Z/p,Z/p) , where ,to(s)=q(sp3+(s--1)p2+(s--1)p+s--1)+s--4 in the classical Adams spectral sequence. The method of proof is by May spectral sequence.